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-2x^2=30x+100
We move all terms to the left:
-2x^2-(30x+100)=0
We get rid of parentheses
-2x^2-30x-100=0
a = -2; b = -30; c = -100;
Δ = b2-4ac
Δ = -302-4·(-2)·(-100)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10}{2*-2}=\frac{20}{-4} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10}{2*-2}=\frac{40}{-4} =-10 $
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